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Part (i)
The function f(x) is continuous in the interval [6<=x<=-2].Since its a polynomial.
Part (ii)
f(x) is differentiable in the interval [6Part (iii)
Find out if f(6)=f(-2).
f(x)=x²-4x-12
f(x)=(x-6) (x+2)
f(6)=(6-6) (6+2)=0
f(-2)=(-2-6) (-2+2)=0
f(6)=f(-2)=0 there will exist atleast a point c in open interval [a f(x)=x²-11x+24
f'(x)=2x-11
f’(c)=2c-11
0=2c-11
11/2=c
[3<=c<=8]
Kibet Koina answered the question on January 23, 2019 at 13:07
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